关于#c++#结构体的赋值问题，如何解决？

Question

结构体初始化时，用一个函数赋值为啥会出毛病呢，求帮忙

#include <iostream>
#include <string>

using namespace std;



struct free_throws
{
    string name;
};

const free_throws & clone2(free_throws &ft){
    free_throws newguy; //创建了临时变量
    newguy = ft;
    return newguy; 

const free_throws & clone3(free_throws &ft){
    free_throws * newguy; //创建了临时变量
    *newguy = ft;
    return *newguy; 
}

int main(){
   struct free_throws ft_{"abc"};
    
    cout << "ft_ address = " << &ft_<< endl;
    // const struct free_throws ft_2 = clone2(ft_);

    const struct free_throws ft_2 = clone3(ft_);
    // struct free_throws ft_2;
    // ft_2 = clone3(ft_);
    cout << "ft2_ address = " << &ft_2<<endl;
    
}

现在的代码，只打印了一行

如果这样写

 struct free_throws ft_{"abc"};
    
    cout << "ft_ address = " << &ft_<< endl;
    // const struct free_throws ft_2 = clone2(ft_);

    // struct free_throws ft_2 = clone3(ft_);
    struct free_throws ft_2;
    ft_2 = clone3(ft_);
    cout << "ft2_ address = " << &ft_2<<endl;
    return 0;

为啥就可以打印两行呢

求解惑

Answer 1

• 这有个类似的问题, 你可以参考下: https://ask.csdn.net/questions/7616199