将信息从一个视图传递到另一个视图

Question

EDIT 1. The results of a query from my database are displayed on my view page. Next to each unique result is a button:

// first_view.php    
<?php echo form_open('controller/method'); ?>
<?php foreach($results_found as $item): ?>
<p><?php echo $item->name ?></p>
<p><?php form_submit('buy','Buy This'); ?></p>

When a user clicks on one of these buttons (lets say button 4), I would like to display the user's choice from the array onto another view.

I've tried using this:

 // first_view.php
<?php echo $this->session->set_userdata('choice',$item); ?>

immediately before

// first_view.php    
<?php echo form_close(); ?>

thinking that the user's final choice would be stored there so I can display it on another view like this:

// second_controller.php
$c = $this->session->userdata('choice');


// second_view.php
echo 'Your Choose: '. $c;

However, what actually displays is the last result displayed on first_view.php, not what the user choose.

My question is, if the user clicked on button 4, how do I get that particular choice displayed onto another view?

END OF EDIT1

ORIGINAL QUESTION

My view page (CodeIgniter) displays the contents of an array in the form of several links. If a user clicks on a link, I want the user to be taken to another view page (via a controller) that gives more information concerning that particular link (which is stored in that particular position in the array)

My question is, how do I access and display the contents of that particular location within the array on the second view file without getting a "Undefined variable error" on the second view?

Here is what I am trying to do in code form

// my_controller.php
$array_name['variable_name'];
$this->load->view('first_view.php');

// first_view.php
<?php foreach($variable_name as $vn): ?>
<?php echo anchor('controller_name' $vn->info ?> // if user clicks on 3rd link
<?php endforeach ?>                              // I want to beable to access
                                                 // index 2 of the array in the 
                                                 // second view file so I can 
                                                 // display more info 
// second_view.php
<?php $vn[2]->info ?>

Answer 1

What you do (as I see it) is that you create form, generate row sumbit buttons and then close that form.

If you want to use forms as indication of what user wants to buy, you have to generate form for each row from result, something like this (it's generated html, but you need to edit it to suit your needs):

Edit (pseudocode wasn't enough :) :

<!-- repeat row times -->
<?php foreach($items as $item): ?>
<p><?php echo $item->name; //echo name ?>
  <?php form_open(/*your settings*/); ?>
  <input type="hidden" name="idToAdd" value="<?php echo $item->id;?>" />
  <input type="submit" value="Buy this" />
  </form>
</p>
<?php endforeach; ?>
<!-- end repeat -->

This way, everytime user clicks 'buy-it' button, different form submits and in your controller/view, you can get id of what user wants to buy through $this->input->post('idToAdd').