douzhong3038 2017-09-12 18:25
浏览 115
已采纳

php什么是函数定义中的“database”关键字

What does the "database" keyword indicate in the function def below? I can't (easily) find documentation for this.

function __construct($arg1, $arg2, database $mysqli = NULL)
  • 写回答

1条回答 默认 最新

  • dqm4977 2017-09-12 18:35
    关注

    This is type hinting. It means that the variable, in this case $mysqli, should meet at least one of the following criteria:

    1. an instance of database class;
    2. an instance from a classe that inherits from a classe named Database;
    3. an instance from a classe that implements an interface named Database.
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 有了解d3和topogram.js库的吗?有偿请教
  • ¥100 任意维数的K均值聚类
  • ¥15 stamps做sbas-insar,时序沉降图怎么画
  • ¥15 unity第一人称射击小游戏,有demo,在原脚本的基础上进行修改以达到要求
  • ¥15 买了个传感器,根据商家发的代码和步骤使用但是代码报错了不会改,有没有人可以看看
  • ¥15 关于#Java#的问题,如何解决?
  • ¥15 加热介质是液体,换热器壳侧导热系数和总的导热系数怎么算
  • ¥100 嵌入式系统基于PIC16F882和热敏电阻的数字温度计
  • ¥15 cmd cl 0x000007b
  • ¥20 BAPI_PR_CHANGE how to add account assignment information for service line