从另一个集合中存在的集合中删除

Question

Let's say I have 2 collections which both have a phone attribute:

$contacts = Contact::all();
$optouts = Optout::all();

I want to update the $contacts collection and remove all which are opted out. So I want to remove all $contacts whose phone is present in $optouts.

How do I do it?

Answer 1

$contacts = Contact::all();
$optouts = Optout::all()->pluck('phone');

$filtered = $contacts->whereNotIn('phone', $optouts);

More info here: https://laravel.com/docs/5.4/collections