js加密代码怎么改写得?

Question

  n.encrypt = function(t) {
                var e, n = [];
                if (void 0 === t)
                    return "";
                e = function(t) {
                    for (var e, n = t.toString(), r = [], i = 0; i < n.length; i++)
                        0 <= (e = n.charCodeAt(i)) && e <= 127 ? r.push(e) : 128 <= e && e <= 2047 ? (r.push(192 | 31 & e >> 6),
                        r.push(128 | 63 & e)) : (2048 <= e && e <= 55295 || 57344 <= e && e <= 65535) && (r.push(224 | 15 & e >> 12),
                        r.push(128 | 63 & e >> 6),
                        r.push(128 | 63 & e));
                    for (var o = 0; o < r.length; o++)
                        r[o] &= 255;
                    return r
                }(t);
                for (var r = 0, i = e.length; r < i; ++r)
                    n.push((5 ^ e[r]).toString(16));
                return n.join("")
            }

// account password生成
function secret(e) {
    var t, n = [];
    if (void 0 === e)
        return "";
    t = function(e) {
        for (var t, n = e.toString(), r = [], o = 0; o < n.length; o++)
            0 <= (t = n.charCodeAt(o)) && t <= 127 ? r.push(t) : 128 <= t && t <= 2047 ? (r.push(192 | 31 & t >> 6),
            r.push(128 | 63 & t)) : (2048 <= t && t <= 55295 || 57344 <= t && t <= 65535) && (r.push(224 | 15 & t >> 12),
            r.push(128 | 63 & t >> 6),
            r.push(128 | 63 & t));
        for (var i = 0; i < r.length; i++)
            r[i] &= 255;
        return r
    }(e);
    for (var r = 0, o = t.length; r < o; ++r)
        n.push((5 ^ t[r]).toString(16));
    return n.join("")
}
console.log(secret("*********dadsdbsbkbk"))
console.log(secret("0191123022478."))

抖店登录的，这个咋个改写得，t换成e,为何，

Answer 1

你这两个图的算法完全一模一样啊，具体算法里，变量用什么命名没什么意义，只要保证算法正确，怎么都可以