dongzhuo3376
dongzhuo3376
2015-04-10 12:46

当我使用Monolog的ExceptionHandler时,如何显示异常?

已采纳

in my usecase, I want to display (when developing) an exception thrown in my php-application.

error_reporting(E_ALL);
ini_set('display_errors', '1');

...

throw new Exception();

This works as it should. When I throw an exception, I will receive it in my http-response from apache (within the returned HTML).

Now, I want to use Monolog for logging. I integrate it, everything works fine, exception is logged to file by Monolog, for example.

error_reporting(E_ALL);
ini_set('display_errors', '1');

...

$exception_log = new Logger('exception');
\Monolog\ErrorHandler::register($exception_log, false, null, false);

...

throw new Exception();

But, the exception is not send in the html-part of the http-response any more. So it is not displayed in my browser when I do my http-request.

How do I use Monolog to log my exceptions, and still "display" them?

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1条回答

  • douye9175 douye9175 6年前

    You need to add you own exception handler.

    For example :

    function echo_exception_handler($e) {
      echo sprintf('Uncaught Exception %s: "%s" at %s line %s', get_class($e), $e->getMessage(), $e->getFile(), $e->getLine());
    }
    set_exception_handler('echo_exception_handler');
    
    $exception_log = new Logger('exception');
    ...
    
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