【matlab】数组生成的值被覆盖

Question

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duration_of_one_win=128;
no_of_secs_bet_con_wins=0;
gap_between_win_starts = duration_of_one_win - no_of_secs_bet_con_wins;
wins.t_start=1:gap_between_win_starts;
wins.t_end=wins.t_start + duration_of_one_win;
%% estimates the RR using Count Orig
rr.t = mean([wins.t_start(:)' ; wins.t_end(:)']); rr.t = rr.t(:);
rr.v = nan(length(rr.t),1);
% Cycle through windows
for win_no = 1 : length(wins.t_start)
    % identify peaks
    diffs_on_left_of_pt = diff(data_resp.v); diffs_on_left_of_pt = diffs_on_left_of_pt(1:(end-1)); diffs_on_left_of_pt = logical(diffs_on_left_of_pt>0);
    diffs_on_right_of_pt = diff(data_resp.v); diffs_on_right_of_pt = diffs_on_right_of_pt(2:end); diffs_on_right_of_pt = logical(diffs_on_right_of_pt<0);
    peaks = find(diffs_on_left_of_pt & diffs_on_right_of_pt)+1;    
    % identify troughs
    diffs_on_left_of_pt = diff(data_resp.v); diffs_on_left_of_pt = diffs_on_left_of_pt(1:(end-1)); diffs_on_left_of_pt = logical(diffs_on_left_of_pt<0);
    diffs_on_right_of_pt = diff(data_resp.v); diffs_on_right_of_pt = diffs_on_right_of_pt(2:end); diffs_on_right_of_pt = logical(diffs_on_right_of_pt>0);
    troughs = find(diffs_on_left_of_pt & diffs_on_right_of_pt)+1;    
    % define threshold
    q3 = quantile(data_resp.v(peaks), 0.75);
    thresh = 0.2*q3;   
    % find relevant peaks and troughs
    extrema = sort([peaks(:); troughs(:)]);
    rel_peaks = peaks(data_resp.v(peaks) > thresh);
    rel_troughs = troughs(data_resp.v(troughs) < 0);    
    % find valid breathing cycles
    % valid cycles start with a peak:
    valid_cycles = zeros(length(rel_peaks)-1,1);
    cycle_durations = nan(length(rel_peaks)-1,1);
    for peak_no = 1 : (length(rel_peaks)-1)        
        % valid if there is only one rel_trough between this peak and the next
        cycle_rel_troughs = rel_troughs(rel_troughs > rel_peaks(peak_no) & rel_troughs < rel_peaks(peak_no+1));
        if length(cycle_rel_troughs) == 1
            valid_cycles(peak_no) = 1;
            cycle_durations(peak_no) = data.t(rel_peaks(peak_no+1)) - data.t(rel_peaks(peak_no));
        end   
        ave_breath_duration = nanmean(cycle_durations);
    end  
    if sum(valid_cycles) == 0 
        rr.v(win_no) = nan;
        continue
    end
    % Calc RR
    % Using average breath length
    rr.v(win_no) = 60/ave_breath_duration;    
end

希望达成的：ave_breath_duration动态赋值，填入rr.v数组
实际上：ave_breath_duration的值固定，rr.v循环出一样的值

Answer 1

该回答引用GPTᴼᴾᴱᴺᴬᴵ
根据提供的代码，ave_breath_duration 是在 for 循环中计算得到的，然后用来计算 rr.v(win_no)。在每个 for 循环迭代中，都会重新计算 ave_breath_duration 的值，因此它是动态赋值的。
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但是在代码中，计算 ave_breath_duration 的语句放在了 for 循环的内部，每次循环迭代都会重新计算一次 ave_breath_duration，而在每次迭代中，ave_breath_duration 只被用来计算一次 rr.v(win_no) 的值，所以在每个迭代中，ave_breath_duration 的值并没有在其他地方使用或保存。
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因此，在 rr.v 中出现相同的值可能是由于其他变量或输入数据的问题，或者是代码逻辑的错误。建议检查输入数据和其他变量的值，以及代码的逻辑是否正确。同时，可以添加调试输出语句以帮助调试程序。