SNMP DateAndTime十六进制字符串在PHP中转换为人类日期

Question

When i want to get the cablemodem event log via SNMP, then i snmpwalk the 'mib-2.69.1.5.8.1' oid, but I had the problem because the SNMP store every event date in 'special' hex-string called DateAndTime format.

(In my case this is a 8 byte hex-string, like this: 07 B2 01 01 00 0A 14 00)

I would like to convert to human date, like this (1970.01.01. 00:10), so I wrote a PHP function:

function hex2date( $hexstring ) {
  $date = "";

  $p = unpack( "H*", substr( $hexstring, 0, 2 ) );  // year (2 byte)
  $date .= hexdec( $p[1] ).".";

  $p = unpack( "H*", substr( $hexstring, 2, 1 ) );  // month (1 byte)
  $date .= sprintf( "%02s", hexdec( $p[1] ) ).".";

  $p = unpack( "H*", substr( $hexstring, 3, 1) );   // day (1 byte)
  $date .= sprintf( "%02s", hexdec( $p[1] ) ).". ";

  $p = unpack( "H*", substr( $hexstring, 4, 1 ) );  // hour (1 byte)
  $date .= sprintf( "%02s", hexdec( $p[1] ) ).":";

  $p = unpack( "H*", substr( $hexstring, 5, 1 ) );  // minute (1 byte)
  $date .= sprintf( "%02s", hexdec( $p[1] ) );

  return ($date);
}

This is work, however for some reason I think that this is not the most elegant solution. Am I right?

Answer 1

For travellers from Google, in this case the device sends an 8 byte SNMP DateAndTime value without timezone information. Check the manual I've linked below. However, obtaining the timezone information follows the same principles.

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Your code should look like this:

// Prepare test data
$binstring = "\x07\xB2\x01\x01\x00\x0A\x14\x00";

$values = unpack('nyear/Cmonth/Cday/Chour/Cminute/Csecond/Cdecisecond', $binstring);
var_dump($values);

Output:

array(7) {
  'year' =>
  int(1970)
  'month' =>
  int(1)
  'day' =>
  int(1)
  'hour' =>
  int(0)
  'minute' =>
  int(10)
  'second' =>
  int(20)
  'decisecond' =>
  int(0)
}

Please refer to the following manual pages:

• SNMP DateAndTime format reference
• PHP function unpack()