python函数find报错

Question

s='1803170101,干文娟,勘查1701,3.92,0.0,2.73,1.0,7.65;1803170102,古丽合妮姆·尤努斯,勘查1701,0.0,0.0,0.4,0.5,0.9;1803170103,洪荐英,勘查1701,3.46,0.0,1.8,0.5,5.76;1803170104,李智彬,勘查1701,2.73,0.3,1.53,0.5,5.06;1803170105,唐思倩,勘查1701,4.09,0.3,4.8,0.5,9.69;1803170106,辛盛涵,勘查1701,4.09,0.3,4.67,0.5,9.56;1803170107,徐凤婷,勘查1701,3.55,0.6,3.2,0.5,7.85;1803170108,虞悦,勘查1701,3.72,0.6,9.0,1.0,14.32;1803170109,艾合买提江·阿布地热木,勘查1701,1.36,0.0,0.6,0.5,2.46;1803170110,陈思为,勘查1701,1.36,0.3,1.67,1.0,4.33;1803170111,陈有鑫,勘查1701,3.75,0.6,4.87,1.0,10.22;1803170112,龚春华,勘查1701,1.36,0.0,0.73,1.0,3.09;1803170114,顾旭珠,勘查1701,1.36,0,1.2,0.5,3.06;1803170115,郭子豪,勘查1701,1.19,0.0,0.93,0.5,2.62;1803170116,何德祺,勘查1701,1.36,0.0,1.27,0.5,3.13;1803170117,何国亮,勘查1701,1.19,0.0,1.6,0.5,3.29;1803170118,何家兴,勘查1701,1.19,0.3,2.27,1.0,4.76;1803170119,何先斌,勘查1701,3.8,0.0,3.4,0.5,7.7;1803170120,胡舒寒,勘查1701,3.92,0.3,3.07,1.0,8.29;1803170121,黄英建,勘查1701,1.36,0.0,2.13,1.0,4.49;1803170122,黎志强,勘查1701,1.36,0.0,0.4,1.0,2.76;1803170123,梁强,勘查1701,3.5,0.0,3.73,1.0,8.23;1803170124,梁宇轩,勘查1701,1.36,0.0,0.73,0.5,2.59;1803170125,林惠明,勘查1701,1.36,0.3,2.6,1.0,5.26;1803170126,马振波,勘查1701,3.46,0.6,7.8,1.0,12.86;1803170127,时英喆,勘查1701,1.02,0.0,1.47,1.0,3.49;1803170129,张栋,勘查1701,0.0,0.0,0.4,1.0,1.4;1803170130,张禄,勘查1701,1.36,0.0,1.2,1.0,3.56;'
print(s.count('勘查'))
print(s.find(begin(input()),end(;)))

这个为什么老是报错，题目如下：
2) 文本中每个人的成绩是以10位学号开始，最后以西文状态下的分号结束。请编程输出某个学号（代码运行时通过键盘输入）的一整条平时成绩记录,如‘1803170108,虞悦,勘查1701,3.72,0.6,9.0,1.0,14.32’。

Answer 1

s = '1803170101,干文娟,勘查1701,3.92,0.0,2.73,1.0,7.65;1803170102,古丽合妮姆·尤努斯,勘查1701,0.0,0.0,0.4,0.5,0.9;1803170103,洪荐英,勘查1701,3.46,0.0,1.8,0.5,5.76;1803170104,李智彬,勘查1701,2.73,0.3,1.53,0.5,5.06;1803170105,唐思倩,勘查1701,4.09,0.3,4.8,0.5,9.69;1803170106,辛盛涵,勘查1701,4.09,0.3,4.67,0.5,9.56;1803170107,徐凤婷,勘查1701,3.55,0.6,3.2,0.5,7.85;1803170108,虞悦,勘查1701,3.72,0.6,9.0,1.0,14.32;1803170109,艾合买提江·阿布地热木,勘查1701,1.36,0.0,0.6,0.5,2.46;1803170110,陈思为,勘查1701,1.36,0.3,1.67,1.0,4.33;1803170111,陈有鑫,勘查1701,3.75,0.6,4.87,1.0,10.22;1803170112,龚春华,勘查1701,1.36,0.0,0.73,1.0,3.09;1803170114,顾旭珠,勘查1701,1.36,0,1.2,0.5,3.06;1803170115,郭子豪,勘查1701,1.19,0.0,0.93,0.5,2.62;1803170116,何德祺,勘查1701,1.36,0.0,1.27,0.5,3.13;1803170117,何国亮,勘查1701,1.19,0.0,1.6,0.5,3.29;1803170118,何家兴,勘查1701,1.19,0.3,2.27,1.0,4.76;1803170119,何先斌,勘查1701,3.8,0.0,3.4,0.5,7.7;1803170120,胡舒寒,勘查1701,3.92,0.3,3.07,1.0,8.29;1803170121,黄英建,勘查1701,1.36,0.0,2.13,1.0,4.49;1803170122,黎志强,勘查1701,1.36,0.0,0.4,1.0,2.76;1803170123,梁强,勘查1701,3.5,0.0,3.73,1.0,8.23;1803170124,梁宇轩,勘查1701,1.36,0.0,0.73,0.5,2.59;1803170125,林惠明,勘查1701,1.36,0.3,2.6,1.0,5.26;1803170126,马振波,勘查1701,3.46,0.6,7.8,1.0,12.86;1803170127,时英喆,勘查1701,1.02,0.0,1.47,1.0,3.49;1803170129,张栋,勘查1701,0.0,0.0,0.4,1.0,1.4;1803170130,张禄,勘查1701,1.36,0.0,1.2,1.0,3.56;'
num = input('请输入学号：')
# 找到开始位置
start = s.find(num)
# 找到结束位置
end = s.find(';', start)
if start > 0 and end > 0:
    print(s[start: end])

有帮助的话，请点采纳该答案~