dsjws44266 2009-11-23 20:40
浏览 20
已采纳

基本的MySQL问题:如何从一个表中获取不在另一个表中的行?

I have a list of usernames (with a column called "username") + other info in my "users" table.

I also have another list of usernames (with a column called "username") in my smaller "recentusers" table.

How can I create a mysql query to get all the usernames that are in the "users" table but not in the "recentusers" table?

I know it is probably very simple, but any help would be appreciated!

  • 写回答

5条回答 默认 最新

  • donglian4770 2009-11-23 20:42
    关注
    select username from users where username not in (select username from recentusers)
    

    Then after the first username add in the other information you want to select as well.

    As pointed out by OMG Ponies, this query will run as fast as using Left Join or Is null.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(4条)

报告相同问题?

悬赏问题

  • ¥15 安卓adb backup备份应用数据失败
  • ¥15 eclipse运行项目时遇到的问题
  • ¥15 关于#c##的问题:最近需要用CAT工具Trados进行一些开发
  • ¥15 南大pa1 小游戏没有界面,并且报了如下错误,尝试过换显卡驱动,但是好像不行
  • ¥15 没有证书,nginx怎么反向代理到只能接受https的公网网站
  • ¥50 成都蓉城足球俱乐部小程序抢票
  • ¥15 yolov7训练自己的数据集
  • ¥15 esp8266与51单片机连接问题(标签-单片机|关键词-串口)(相关搜索:51单片机|单片机|测试代码)
  • ¥15 电力市场出清matlab yalmip kkt 双层优化问题
  • ¥30 ros小车路径规划实现不了,如何解决?(操作系统-ubuntu)