C语言的函数跳转和链表赋值相关问题

Question

问下为何我为一个结点赋值时会进行到主函数的输入age语句 若连续为三个结点赋值 程序会强制结束 不执行92 93行

#include<stdio.h>
#include<math.h>
#include<stdlib.h>
#include<string.h>
 
struct _node{
    int num;
    char name[10];
    char a[10];
    int age;
    struct _node *next;
};
 
struct _node* create()
{
    struct _node* head=(struct _node*)malloc(sizeof(struct _node));
    head->num=0;
    head->name[10]="0";
    head->a[10]="0";
    head->age=0;
    head->next=NULL;
    struct _node* pcurrent=head;
    while(1)
    {
        int number,ag;
        char na[10],b[10];
        printf("请输入学号\n");
        scanf("%d",&number);
        printf("请输入姓名\n");
        scanf("%s",na);    
        printf("请输入性别\n");
        scanf("%s",b);    
        printf("请输入年纪");
        scanf("%d",&ag);
        if(number==0||strcmp(na,"0")==0||strcmp(b,"0")==0||ag==0)
        {
            break;
        }
        struct _node *newnode=(struct _node*)malloc(sizeof(struct _node));
        newnode->num=number;
        strcpy(newnode->name,na);
        strcpy(newnode->a,b);
        newnode->age=ag;
        pcurrent->next=newnode;
        pcurrent=pcurrent->next;
    }
    pcurrent=head->next;
    printf("输出已经赋值的链表");
    while(pcurrent!=NULL)
    {
        printf("%d\n",pcurrent->num);
        pcurrent=pcurrent->next;
    }
    return head;    
    
};
 
int del(struct _node*head,int ag)
{
    struct _node* pcurrent=head->next;
    struct _node* prev=head;
    while(pcurrent!=NULL)
    {
        if(pcurrent->age==ag)
        {
            prev->next=pcurrent->next;
            struct _node* t=pcurrent;
            pcurrent=pcurrent->next;
            free(t);
        }
        if(pcurrent!=NULL)
        {
            prev=prev->next;
            pcurrent=pcurrent->next;
        }
    }
    pcurrent=head->next;
    printf("删除对应年纪后的链表");
    while(pcurrent!=NULL)
    {
        printf("%s\n",pcurrent->name[10]);
        pcurrent=pcurrent->next;
    }
    
}   
    
int main()
{
    struct _node *head=create(); 
    int age;
    printf("请输入一个想要删除的年纪");
    scanf("%d",&age);
    del(head,age);   
        
}

Answer 1

head->name[10]="0"; 不能这么写啊
name[10]是char类型，表示name数组的第10个元素，这是越界访问。而且"0"是字符串，也不能赋值给一个字符的
head->name[10]="0"; 改为strcpy(head->name,"0");