douduonang3169 2019-05-09 10:32
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SQL Count返回0

I have been trying to count the number of paths present in my table.

enter image description here

I am trying the following query

$db_con->query("SELECT COUNT(path) FROM mytable WHERE username='Rbiaali' AND path='C:\MAMP\htdocs\files\Rbiaali\9-5-2019 01 55 AM.zip'")->fetchColumn();

Also even if i use the below it is returning the same value: 0

path LIKE 'C:\MAMP\htdocs\files\Rbiaali\9-5-2019 01 55 AM.zip%'

As in the table, we can see that there are 6 entries with the path.

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  • duanran6441 2019-05-09 10:35
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    You need to escape the backslashes, because backslash is the escape character in MySQL. \f is a form-feed character.

    $db_con->query("SELECT COUNT(path) FROM mytable WHERE username='Rbiaali' AND path='C:\\MAMP\\htdocs\\files\\Rbiaali\\9-5-2019 01 55 AM.zip'")->fetchColumn();
    

    If you're getting the path from a variable, use a prepared statement:

    $stmt = $db_con->prepare("SELECT COUNT(path) FROM mytable WHERE username=:user AND path=:path");
    $stmt->execute([":user" => $u, ":path" => $p]);
    $stmt->fetchColumn();
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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