JavaScript数组变化

Question

如何把obj3替换掉arr数组里面的info消息，得出res

const arr = [{
      content: {
        info: {
          stu1: {
            name: '张三',
            age: 12,
            school:'南校'
          },
          stu2:{
            name:'李四',
            age:12,
            school:'北校'
          }
        }
      }
    }, {
      content: {
        info: {
          stu1: {
            name: '张三',
            age: 12,
            school:'南校'
          },
          stu2:{
            name:'李四',
            age:12,
            school:'北校'
          }
        }
      }
    }]
    const obj3={
      info: {
          stu1: {
            name: '张三',
            age: 12
          },
          stu2:{
            name:'李四',
            age:12
          },
          stu3:{
            name:'王五',
            age:23
          }
        }
    }

Answer 1

根据name值决定是否删除、添加arr中对应项？还是根据stu1,stu2,stu3这种键名称？

下面这个是根据stu1,stu2,stu3这种键名称

///arr和obj3数据
    let keys = Object.keys(obj3.info);
    arr.forEach(item => {
        //新增
        keys.forEach(key => {
            if (!item.content.info[key]) {
                item.content.info[key] = obj3.info[key];
            }
        });
        //删除
        Object.keys(item.content.info).forEach(key => {
            if (!obj3.info[key]) delete item.content.info[key]
        })
    });
    console.log(JSON.stringify(arr, null, 2))

下面根据name

    ///得到同一个info下的不重名键名称
    function getKey(info) {
        let i = 1;
        while (true) {
            if (!info['stu' + i]) return 'stu' + i
            i++;
        }
    }

    let key_names = Object.keys(obj3.info).map(i => ({ key: i, name: obj3.info[i].name }));//得到obj3中的name值和键值对象集合
    arr.forEach(item => {
        let keys = Object.keys(item.content.info), arrNames = keys.map(i => item.content.info[i].name)

        //删除
        keys.forEach(key => {
            if (!key_names.some(i => item.content.info[key].name == i.name)) delete item.content.info[key]
        });

        //添加
        key_names.forEach(i => {
            if (!arrNames.some(x => i.name == x)) item.content.info[getKey(item.content.info)] = obj3.info[i.key];
        })
    });
    console.log(JSON.stringify(arr, null, 2))