duan5362 2012-02-01 19:58
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php如何循环遍历数组直到满足条件?

I have a database table with images that I need to display. In my view, I'd like to display UP TO 10 images for each result called up. I have set up an array with the 20 images that are available as a maximum for each result (some results will only have a few images, or even none at all). So I need a loop that tests to see if the array value is empty and if it is, to move onto the next value, until it gets 10 results, or it gets to the end of the array.

What I'm thinking I need to do is build myself a 2nd array out of the results of the test, and then use that array to execute a regular loop to display my images. Something like

<?php 
  $p=array($img1, $img2.....$img20);

  for($i=0; $i<= count($p); $i++) {
    if(!empty($i[$p])) {
    ...code
    }
  }
?>

How do I tell it to store the array values that aren't empty into a new array?

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  • douhao7677 2012-02-01 20:19
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    you could do something like:

    $imgs = array(); $imgs_count = 0;
    foreach ( $p as $img ) {
        if ( !empty($img) ) {
            $imgs[] = $img;
            $imgs_count++;
        }
        if ( $imgs_count === 10 ) break;
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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