分组密码算法misty1的子密钥生成算法c++实现

Question

分组密码算法MISTY1的子密钥生成算法c++实现，各位可以帮助一下么，具体就是输入（16位二进制比特输入和16位二进制比特密钥），经过FI函数输出（16位二进制比特输出），谢谢！

Answer 1

参考

#include <iostream>
#include <vector>
#include <bitset>

using namespace std;

void generateSubKeys(const bitset<128>& key, vector<bitset<64>>& subKeys) {
    // S-Box values
    const unsigned char sBox[256] = {
        // values here
    };

    // XOR constants
    const unsigned int xorConst[8] = {
        0x00000000, 0x5A827999, 0x6ED9EBA1, 0x8F1BBCDC,
        0xA953FD4E, 0xC2A12D9B, 0xD7C45034, 0xE7D3FBC8
    };

    // Convert key to two 64-bit halves
    bitset<64> K1(key.to_ulong() >> 64);
    bitset<64> K2(key.to_ulong());

    // Generate 4 subkeys per round
    for (int i = 0; i < 4; i++) {
        // Compute Fi function
        bitset<64> F = ((K1 >> 32) ^ K2) & 0x7FFFFFFF;
        F ^= xorConst[i];
        F = bitset<64>(sBox[F.to_ulong() >> 24]) << 24 |
            bitset<64>(sBox[(F.to_ulong() >> 16) & 0xFF]) << 16 |
            bitset<64>(sBox[(F.to_ulong() >> 8) & 0xFF]) << 8 |
            bitset<64>(sBox[F.to_ulong() & 0xFF]);
        F = ((F << 32) | (F >> 32)) & 0xFFFFFFFFFFFFFFFE;

        // Compute new values for K1 and K2
        bitset<64> tmp = K1;
        K1 = (K1 << 8) | (K2 >> 56);
        K1 ^= F;
        K2 = (K2 << 8) | (tmp >> 56);

        // Generate subkeys
        if (i % 2 == 0) {
            subKeys.push_back(K1);
            subKeys.push_back(K2);
        }
    }
}

int main() {
    // Example key
    bitset<128> key("00000000000000000000000000000000");

    // Generate subkeys
    vector<bitset<64>> subKeys;
    generateSubKeys(key, subKeys);

    // Print subkeys
    for (int i = 0; i < 8; i++) {
        cout << "K" << i << ": " << subKeys[i].to_ulong() << endl;
    }

    return 0;
}