各位看看这个链表的循环怎么结束

Question

int count = 0;
struct Student {
    char name[100];
    int number;
    struct Student* next;
};
struct Student* Creat()
{
    struct Student* head = NULL;
    struct Student* end, * new1;
    end = new1 = (struct Student*)malloc(sizeof(struct Student));
    printf("请输入姓名\n");
    scanf("%s", &new1->name);
 
    while (new1->name!=NULL)//为什么我输入为空，跳不出循环，怎么输入才能跳出循环啊
    {
 
        count++;
        if (count == 1)
        {
            new1->next = head;
            head = new1;
            end = new1;
        }
        else
        {
            new1->next = NULL;
            end->next = new1;
            end = new1;
        }
        new1 = (struct Student*)malloc(sizeof(struct Student));
        scanf("%s", &new1->name);
    }
    free(new1);
    return head;
}
void print(struct Student* head)
{
    struct Student* temp;
    temp = head;
    int n = 1;
    printf("--有%d个成员:----\n", count);
    printf("\n");
    while (temp != NULL)
    {
        printf("NO:%d成员:\n", n);
        printf("姓名:%s\n", temp->name);
        printf("\n");
        temp = temp->next;
        n++;
    }
}
int main()
{
    struct Student* head;
    head = Creat();
    print(head);
    return 0;
}

Answer 1

new1->name!=NULL 永远不会是空啊
改为:
while(strlen(new1->name) == 0)
或者while(new1->name[0] != '\0')