如何用栈进制转换 输出乱码？

Question

用栈进制转换 输出乱码

#define _CRT_SECURE_NO_WARNINGS 1
#include<stdio.h>
#include<stdlib.h>
#include<assert.h>
#include<string.h>
#define MAXSIZE 2000
#define OVERFLOW -2
#define ERROR 0
#define OK 1
#define Status int

typedef int SELemType;
typedef struct
{
    SELemType* base;
    SELemType* top;
    int stacksize;
}SqStake;
Status InitStack(SqStake* S)
{
    S->base = (SELemType*)malloc(MAXSIZE * sizeof(SELemType));
    if (!S->base)exit(OVERFLOW);
    S->top = S->base;
    S->stacksize = MAXSIZE;
    return OK;
}
Status Push(SqStake* S, SELemType e) {
    if (S->top - S->base == S->stacksize)
        return ERROR;
    *S->top++ = e;
    return OK;



}
Status Pop(SqStake* S, SELemType* e) {
    if (S->base == S->top)
        return ERROR;
    --S->top;
    e = *S->top;
    return OK;


}
int StackEmpty(SqStake S)
{
    if (S.top ==S.base)
    {
        return 0;
    }
    else
    {
        return 1;
    };



}


void conversion()
{
    SqStake S;
    SELemType h;
    InitStack(&S);
    printf("请输入非负的数：\n");
    scanf("%d", &h);
    while (h)
    {

        Push(&S, h % 8);
        h = h / 8;
    }
    SELemType e;
    while (StackEmpty(S))
    {
    
        Pop(&S, &e);
        printf("%d", e);
    }
}


void main()
{
    conversion();
    system("pause");
}

Answer 1

在 Pop 函数中，需要将传入的指针 e 解引用才能将弹出的栈顶元素赋值给它，所以需要修改 Pop 函数的实现，将 e = *S->top; 改为 *e = *(--S->top)。