donh61500 2017-09-19 05:35
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在Symfony3 / PHP中通过字符串变量创建新的Object

I send variables to my route via an ajax post. Based on the value of my type value I create a new Object, like this:

if($request->get('type') === 'HardwareType'){
    $e = new HardwareType();
}else if($request->get('type') === 'SetupType'){
    $e => new SetupType();
}else{
    new NotFoundHttpException();
}

This gets out of hand quickly even with a switch I think its still "ugly". Is there any way I could do sth. like this:

$e = new $request->get('type')();

Any hint appreciated

EDIT I use the class(es) with this use AppBundle\Entity\HardwareType; etc.

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  • draw62188 2017-09-19 05:37
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    you can do this:

    $e = $request->get('type');
    $class = new $e();
    

    If you need you can add the path or the class like this:

    $e = 'AppBundle\Entity\' . $request->get('type');
    

    Obviously you need to add use at the begin of the file and you can check before the new if the class exist or not

    Like this:

    if (!class_exists($e)) {
       //exception
    }
    
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