java stream 如何实现有一个不符合就退出

Question

只要有一个奇数就退出

        boolean hasOdd = false;
        List<Integer> list = Arrays.asList(2, 1, 3, 4);
        for (Integer integer : list) {
            if (integer % 2 == 0) continue;
            hasOdd = true;
            break;
        }
        System.out.println(hasOdd);

请问佬们，如何用java stream 一行实现如上效果？请教！

Answer 1

List<Integer> list = Arrays.asList(2, 1, 3, 4);
boolean hasOdd = list.stream().anyMatch(i -> i % 2 != 0);
System.out.println(hasOdd);