dousu1900 2011-08-02 20:08
浏览 45

解析错误:语法错误

what is this error ?

Parse error: syntax error, unexpected T_VAR in D:\xampp\htdocs\mehdi\application\libraries\phpass-0.1\PasswordHash.php on line 32

code:

$iteration_count_log2 = $params['phpass_hash_strength'];
        $portable_hashes = $params['phpass_hash_portable']; 
    var $itoa64; //line 32
    var $iteration_count_log2;
    var $portable_hashes;
    var $random_state;
  • 写回答

2条回答 默认 最新

  • dry0106 2011-08-02 20:11
    关注

    You must not use var to declare a variable : just assign a value to it, when you need it :

    $your_variable = 5647;
    


    And if you really want your variables listed beforehand, just assign something that would mean no-value to them, like, for instance, null :

    $your_variable = null;
    


    Just so you know : var was used, in PHP 4 (and, as such, is still valid in PHP 5, for that same usage) to declare classes properties.

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