Java 循环结构 if else

Question

1)输入年份如2016;做合法性判断，如果输入不正确，重新输入，直到输入正确的年份
(2)接着输入月份如2;做合法性判断，如果输入不正确，重新输入，直到输入正确的月份
(3)打印出2016年是闰年，2月有29天
(4)重复的年份和月份的查询，提示用户是否继续查询，yes继续查询，no查询停止。

Answer 1

参考下思路

import java.util.Scanner;

public class LeapYearAndDaysInMonth {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);

        String input = "yes";
        while (input.equals("yes")) {

            int year;
            do {
                System.out.print("请输入年份（如2016）：");
                while (!scanner.hasNextInt()) {
                    System.out.print("输入不正确，请重新输入年份（如2016）：");
                    scanner.next();
                }
                year = scanner.nextInt();
            } while (year <= 0);

            int month;
            do {
                System.out.print("请输入月份（1-12）：");
                while (!scanner.hasNextInt()) {
                    System.out.print("输入不正确，请重新输入月份（1-12）：");
                    scanner.next();
                }
                month = scanner.nextInt();
            } while (month < 1 || month > 12);

            boolean isLeapYear = false;
            if (year % 4 == 0) {
                if (year % 100 == 0) {
                    if (year % 400 == 0) {
                        isLeapYear = true;
                    }
                } else {
                    isLeapYear = true;
                }
            }

            int daysInMonth = 0;
            if (month == 2) {
                if (isLeapYear) {
                    daysInMonth = 29;
                } else {
                    daysInMonth = 28;
                }
            } else if (month == 4 || month == 6 || month == 9 || month == 11) {
                daysInMonth = 30;
            } else {
                daysInMonth = 31;
            }

            System.out.println(year + "年" + (isLeapYear ? "是" : "不是") + "闰年，" + month + "月有" + daysInMonth + "天。");

            do {
                System.out.print("是否继续查询？（yes或no）");
                input = scanner.next().toLowerCase();
            } while (!input.equals("yes") && !input.equals("no"));
        }
    }
}