你可以在CGI脚本的输出中嵌入PHP代码吗？

Question

I have a CGI based form that I am working with and I would like to be able to include some PHP code in the generated results. However, when I do this, the PHP does not appear to get processed and just ends up being displayed in the resulting web page.

Is what I am doing actually possible or am I missing something?

Thanks.

Answer 1

No, that's not possible. You could however, in a PHP script, include('http://url.to/cgi/script'); and then point your browser at the PHP script rather than the CGI script. This will cause PHP to open a new connection to the server, execute the CGI script, and then parse it's output as if it were a PHP script.

EDIT2: Here's how you could do it with postdata including file uploads:

// Edit to match your CGI URI:
$url_to_cgi = "http://{$_SERVER['SERVER_NAME']}/cgi-bin/something.cgi";

$curl = curl_init($url_to_cgi);
curl_setopt($curl,CURLOPT_POST, true);
curl_setopt($curl,CURLOPT_RETURNTRANSFER, true);

// Pass POSTDATA along to the CGI script:
$postdata = $_POST;

// If we have file uploads, pass those along too:
if(is_array($_FILES)) foreach($_FILES as $key => $file)
  $post[$key] = "@{$file['tmp_name']}";

curl_setopt($curl,CURLOPT_POSTFIELDS, $postdata);

$file = tempnam('/tmp','php-curl-');
file_put_contente($file, curl_exec($curl);

include($file);

unlink($file);

Please note that's untested...