dssqq64884 2017-01-27 07:47
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表单提交后,PHP ::单选按钮值始终设置为“打开”

Here is my form:

<form method="post" enctype="multipart/form-data">
<input type="radio" name="sex" value="male" checked />
<input type="radio" name="sex" value"female"/>
<input type="submit" name="btn">
</form>

$_POST['sex'] = always I see the below output for the radio button:

See = string 'on'

It always gives "on" instead of male or female. This is what I have put in the form.

Am I doing something wrong here?

Please help.

If I use SELECT box, then it works well. But I need to make it work using radio button.

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2条回答 默认 最新

  • dti70601 2017-01-27 08:40
    关注
    <form method="post" enctype="multipart/form-data">
    Male : <input type="radio" name="sex" value="male" checked /><br/>
    Female : <input type="radio" name="sex" value="female"/><br/>
    <input type="submit" name="btn">
    </form>
    
    <?php
    error_reporting(0);
    echo $_REQUEST['sex'];
    ?>
    

    Above code is working, Changes

    value = female
    

    you forgot to add = sign

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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