PHP MYSQL查询结合并添加两个平衡结果

Question

Somebody please help me to solve my sql query i have already spend two days for this....

i have a MYSQL query given below

(SELECT
  c.cl_list as cl_list,
  c.name as name,
  pc.value as value,
  count( pc.value) as total
FROM
  projs p 
  LEFT JOIN classify_proj_new pc 
    ON p.proj_id = pc.proj_id_fk
  LEFT JOIN classify_list c 
    ON c.cl_list = pc.class_id_fk
WHERE
  MATCH ( p.title ) AGAINST ( 'jerm'  IN BOOLEAN MODE )
GROUP BY 
  c.cl_list,
  pc.value)
UNION ALL
(SELECT
  c.cl_list as cl_list,
  c.name as name,
  pc.value as value,
  count( pc.value) as total
FROM
  jerm p 
  LEFT JOIN classify_jerm_new pc
    ON p.jerm_id = pc.jerm_id_fk
  LEFT JOIN classify_list c
    ON c.cl_list = pc.class_id_fk
WHERE
  MATCH ( p.jermname ) AGAINST ( 'jerm'  IN BOOLEAN MODE )
GROUP BY
  c.cl_list,
  pc.value)

Which Gives a result of (below):

  cl_list      name              value        total
------------------------------------------------------------------------------------
    1       department         jewller          2
    3       price                 50            2
    6       color                blue           1
    6       color                Red            2
    1       department         jewller          1
    6       color                Red            1

but i am trying to get a result which can add the repeating value's total and avoid repeating value....some thing like this (below):

  cl_list      name              value        total
------------------------------------------------------------------------------------
    1       department         jewller          3
    3       price                 50            2
    6       color                blue           1
    6       color                Red            3

somebody please help me i am very sad about my output...

Thank you very much in advance...

Answer 1

Select from your query and group by cl_list, name and value:

SELECT
  cl_list,
  name,
  value,
  sum(total) as total
FROM (
  -- your current query here ...
) data
GROUP BY
  cl_list,
  name,
  value