doudeng8691 2012-09-12 02:55
浏览 70
已采纳

如果($ _ FILES ['files'] ['name']!=“”)运行if文件,如果没有文件头痛就不要运行

Not having any luck with my other thread with specific code so if I can I'd like to ask how people would go about getting this to work.

I have an page where my client edits details of a property displayed on a property list, say they edit text and don't add any images to this property.

HTML form works fine, I'm just looking at the php.

Example:

If files selected then run this script as an include
If no files selected then exit

Something like this...

if($_FILES['files']['name']!="")
 {
 Do this
 }
  else
{
exit();
}

I'm going mental trying to figure this out so any help or suggestions would be great. I have tried a few variations and variations on top of those variations and nothing seems to work so far.

Cheers

  • 写回答

1条回答 默认 最新

  • duannai5879 2012-09-12 02:57
    关注

    Use isset() orempty() constructs. (For more information read PHP doc)

    if(!empty($_FILES['files']['name']))
     {
      //
     }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 stable diffusion
  • ¥100 Jenkins自动化部署—悬赏100元
  • ¥15 关于#python#的问题:求帮写python代码
  • ¥20 MATLAB画图图形出现上下震荡的线条
  • ¥15 关于#windows#的问题:怎么用WIN 11系统的电脑 克隆WIN NT3.51-4.0系统的硬盘
  • ¥15 perl MISA分析p3_in脚本出错
  • ¥15 k8s部署jupyterlab,jupyterlab保存不了文件
  • ¥15 ubuntu虚拟机打包apk错误
  • ¥199 rust编程架构设计的方案 有偿
  • ¥15 回答4f系统的像差计算