从JavaScript调用php脚本

I have spent all morning trying to figure out how I can call a PHP script from my JavaScript function and then return a value to output. I am not sure whether I can do this with just JavaScript or whether I have to include some Ajax aswell?

Here is the main page

<script>
    $("document").ready(function (){       
        $("select").change(function(){
            var currentValue = parseInt($(this).find("option:selected").val());
            //Call Script script.php here
            $("#output").html(result);
        })
    }); 
</script>   
</head>
<body>
    <select name="select">
        <option value='1' >1</option>
        <option value='2'>2</option>
        <option value='3'>3</option>
    </select>
    <div id="output"><!---OUTPUT HERE----></div>

And here is the script I want to call (I have simplified it all down to make it easier to understand)

<?php
    $result = $currentValue + 1;
?>

Basically I want it to read in the currentValue variable and output the result variable back to the webpage, to be outputted again.

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2条回答默认最新

dongzecai0684 2012-07-21 11:53

关注

// Javascript:
$.ajax({
            type: "GET",
            url: "example.com/script.php?currentValue="+currentValue ,
            dataType: "json",
            statusCode: {
                200: function (result)
                {
                    $("#output").html(result.value);
                }
            }
        });


// PHP 
<?php 
$result = $_GET["currentValue"] + 1;
echo json_encode(array("value" => $result));

 ?>

本回答被题主选为最佳回答 , 对您是否有帮助呢?