如何在php中获取xml节点的属性值？

Question

I'm using simplexml to read a xml file. So far i'm unable to get the attribute value i'm looking for. this is my code.

          if(file_exists($xmlfile)){
              $doc = new DOMDocument();
              $doc->load($xmlfile);
              $usergroup = $doc->getElementsByTagName( "preset" );
              foreach($usergroup as $group){         
                 $pname = $group->getElementsByTagName( "name" );
                 $att = 'code';
                 $name = $pname->attributes()->$att; //not working

                 $name = $pname->getAttribute('code'); //not working
                 if($name==$preset_name){
                     echo($name);
                      $group->parentNode->removeChild($group);
                 }
              }
          }

and my xml file looks like

<presets>
<preset>
 <name code="default">Default</name>
  <createdBy>named</createdBy>
  <icons>somethignhere</icons>
 </preset>
</presets>

Answer 1

Actually question in my head includes deleting a node as well , mistakenly i could not add it. So in my point of view this is the complete answer, i a case if someone else find this useful. This answer doesn't include SimpleXMLElement class because how hard i tried it didn't delete the node with unset(); . So back to where i was , i finally found an answer. This is my code. and its Simple!!!

if(file_exists($xmlfile)){
              $doc = new DOMDocument();
              $doc->load($xmlfile);
              $presetgroup = $doc->getElementsByTagName( "preset" );
              foreach($presetgroup as $group){       
                 $pname = $group->getElementsByTagName( "name" );
                  $pcode = $pname->item(0)->getAttribute('code');
                 if($pcode==$preset_name){
                      echo($preset_name);
                      $group->parentNode->removeChild($group);
                 }
              }
          }
        $doc->save($xmlfile);