如何按订单状态排序数组

Question

I have an array with date, status and summ:

Array
(
    [0] => Array
        (
            [date] => 2019-07-06 14:01:52
            [status] => paid
            [summ] => 100

        )

    [1] => Array
        (
            [date] => 2019-07-02 12:22:31
            [summ] => 320
            [status] => pending
        )

    [2] => Array
        (
            [date] => 2019-07-01 18:43:58
            [summ] => 100
            [status] => pending
        )

    [3] => Array
        (
            [date] => 2019-06-26 14:01:52
            [status] => canceled
            [summ] => 200
        )

i need to sort this array by status first (1.pending, 2.paid, 3.canceled), and then by date (new at the top).

Order which i nedd:

pending 2019-07-02 12:22:31 pending 2019-07-01 18:43:58 paid 2019-07-06 14:01:52 canceled 2019-06-26 14:01:52

with date i don't have any problems:

usort($new11, function($a, $b) {
    return strtotime($b['date']) - strtotime($a['date']);
});

But how to sort by status in order which i need?

Thanx:)

Answer 1

you can use Spaceship:

<?php

    $new11 = [
        [
            'date' => '2019-07-06 14:01:52',
            'status' => 'paid',
            'summ' => 100,
        ],
        [
            'date' => '2019-07-02 12:22:31',
            'status' => 'pending',
            'summ' => 320,
        ],
        [
            'date' => '2019-07-01 18:43:58',
            'status' => 'pending',
            'summ' => 100,
        ],
        [
            'date' => '2019-06-26 14:01:52',
            'status' => 'canceled',
            'summ' => 200,
        ],
    ];

    $pending = 3;
    $paid = 2;
    $canceled = 1;

    usort($new11, function($a, $b) use ($pending, $paid, $canceled) {
        return (${$b['status']} <=> ${$a['status']}) * 10 +
               (strtotime($b['date']) <=> strtotime($a['date']));
    });


    var_dump($new11);

demo