一个Python编程

Question

这是一道编程题目，想知道这个题目如何编写(感谢1111111111111111111111111111111111111111111111111111111111111111111111)

Answer 1

import re

def validate_id_number(id_number):
    pattern = re.compile(r'^\d{17}[\dXx]$')
    if not pattern.match(id_number):
        return False
    factors = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2, 1]
    check_code_dict = {0: '1', 1: '0', 2: 'X', 3: '9', 4: '8', 5: '7', 6: '6', 7: '5', 8: '4', 9: '3', 10: '2'}
    check_code = check_code_dict[sum([int(id_number[i]) * factors[i] for i in range(17)]) % 11]
    return check_code.upper() == id_number[-1].upper()

def get_birthday_and_gender(id_number):
    birthday = id_number[6:14]
    year = int(birthday[0:4])
    month = int(birthday[4:6])
    day = int(birthday[6:8])

    if id_number[16] in ['0', '1', '2', '3', '4', '5']:
        century = '19'
    else:
        century = '20'

    gender_code = int(id_number[16])
    if gender_code % 2 == 0:
        gender = '女'
    else:
        gender = '男'

    birthday = century + str(year) + '-' + str(month) + '-' + str(day)

    return birthday, gender


id_number = input('请输入18位身份证号码：')

if validate_id_number(id_number):
    birthday, gender = get_birthday_and_gender(id_number)
    print('生日：', birthday)
    print('性别：', gender)
else:
    print('身份证号码不合法')