dongmu1989 2017-07-12 09:42 采纳率: 0%
浏览 33
已采纳

数据未插入但使用bind_param没有错误PHP

i have a simple code to input data to my database using prepare and bind_param

there is no error but my data are not inputted into database

  $stmt1 = $mysqli -> prepare ("INSERT INTO equipment(eqp_type, eqp_name, eqp_qty, eqp_usd, $eqp_idr) VALUES (?,?,?,?,?)");
  $stmt1->bind_param('sssss',$eqp_type, $eqp_name, $eqp_qty, $eqp_usd, eqp_idr);
  $eqp_type = 'BUC';
  $eqp_name = 'BUC test';
  $eqp_qty = '1';
  $eqp_usd = '0';
  $eqp_idr = '0';
  $stmt1->execute();

is there any idea why there is no error but my data are not inputted into database ?

  • 写回答

3条回答 默认 最新

  • dst2017 2017-07-12 09:45
    关注

    You might forget to execute it.

    You can do it with following code:

    $stmt1->execute();
    

    So your code would look as follows:

    $eqp_type = 'BUC';
    $eqp_name = 'BUC test';
    $eqp_qty = '1';
    $eqp_usd = '0';
    $eqp_idr = '0';
    $stmt1 = $mysqli -> prepare ("INSERT INTO equipment(eqp_type, eqp_name, eqp_qty, eqp_usd, eqp_idr) VALUES (?,?,?,?,?)");
    $stmt1->bind_param('sssss',$eqp_type, $eqp_name, $eqp_qty, $eqp_usd, $eqp_idr);
    $stmt1->execute();
    

    Manual

    PHP: mysqli_stmt::bind_param

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥15 乌班图ip地址配置及远程SSH
  • ¥15 怎么让点阵屏显示静态爱心,用keiluVision5写出让点阵屏显示静态爱心的代码,越快越好
  • ¥15 PSPICE制作一个加法器
  • ¥15 javaweb项目无法正常跳转
  • ¥15 VMBox虚拟机无法访问
  • ¥15 skd显示找不到头文件
  • ¥15 机器视觉中图片中长度与真实长度的关系
  • ¥15 fastreport table 怎么只让每页的最下面和最顶部有横线
  • ¥15 java 的protected权限 ,问题在注释里
  • ¥15 这个是哪里有问题啊?