遍历所有页面的链接，并保存在列表a中

Question

#如何在以下代码中添加点击next按钮获取每一页链接，直到无法点击next或页面结束，将输出的所有链接保存到我的a[]中

```python
a = {}
for links in driver.find_elements(By.XPATH,
                                  '//*[@class="a-link-normal s-underline-text s-underline-link-text s-link-style '
                                  'a-text-normal"]'):
    sleep(1)

    print(links.get_attribute('href'))
    # a.append(links.get_attribute('href'))
# 等待10秒直到元素完善

WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.CSS_SELECTOR, "div.s-search-results")))

# 获取搜索结果的链接
links = driver.find_elements(By.CSS_SELECTOR, 'a.a-link-normal.s-no-outline')
url_list = [link.get_attribute('href') for link in links]
for url in url_list:
    driver.get(url)
    try:
        # 等待页面加载完成
        WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.ID, "productTitle")))
        # 获取数据链接
        seller_link = driver.find_element(By.ID, "sellerProfileTriggerId").get_attribute('href')
        #点击滑动元素
        driver.execute_script("arguments[0].scrollIntoView();", driver.find_element(By.ID, "sellerProfileTriggerId"))
        driver.refresh()
        sleep(3)
        driver.find_element(By.ID, "sellerProfileTriggerId").click()
        seller_box = driver.find_element(By.CSS_SELECTOR,
                                         '#page-section-detail-seller-info > div:nth-child(1) > div:nth-child(1)').text
    except NoSuchElementException:
        continue
    # 输出链接
    print(seller_link)
    # 输出要获取的内容
    print(seller_box)

#点击下一页元素为linkText=Next

```

Answer 1

可以使用while循环和try-except语句来实现点击next按钮获取每一页链接的功能，直到无法点击next或页面结束。具体代码如下：

a = []
while True:
    # 遍历当前页面的链接
    for link in driver.find_elements(By.XPATH, '//*[@class="a-link-normal s-underline-text s-underline-link-text s-link-style a-text-normal"]'):
        a.append(link.get_attribute('href'))
        print(link.get_attribute('href'))
    try:
        # 点击下一页按钮
        next_button = driver.find_element(By.LINK_TEXT, 'Next')
        next_button.click()
        # 等待页面加载完成
        WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.CSS_SELECTOR, "div.s-search-results")))
    except NoSuchElementException:
        # 如果找不到下一页按钮，则退出循环
        break
# 输出所有链接
print(a)