函数曲线的离散化 急！

Question

一个函数x(t)=-2tsin(tt)，0≤t≤8，从0开始，以△t=0.01、0.02，0.04、0.08、0.1，0.25，0.5、1等为间隔，分别绘制不同△t下的x(t)的离散曲线。每个离散样本点可用‘’显示，程序采用JAVA实现。

Answer 1

专门配置环境帮你弄了，记得采纳一下哦！谢谢啦！

import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.chart.LineChart;
import javafx.scene.chart.NumberAxis;
import javafx.scene.chart.XYChart;
import javafx.stage.Stage;

public class DiscretizeFunctionCurve extends Application {

    @Override
    public void start(Stage stage) {
        stage.setTitle("Discrete Curve");

        final NumberAxis xAxis = new NumberAxis();
        final NumberAxis yAxis = new NumberAxis();
        xAxis.setLabel("t");
        yAxis.setLabel("x(t)");

        final LineChart<Number, Number> lineChart = new LineChart<>(xAxis, yAxis);
        lineChart.setTitle("Discrete Curve: x(t)=-2tsin(t^3)");

        double[] intervals = {0.01, 0.02, 0.04, 0.08, 0.1, 0.25, 0.5, 1};
        for (double interval : intervals) {
            XYChart.Series series = new XYChart.Series();
            series.setName("Interval: " + interval);
            for (double t = 0; t < 8; t += interval) {
                double x = -2 * t * Math.sin(Math.pow(t, 3));
                series.getData().add(new XYChart.Data(t, x));
            }
            lineChart.getData().add(series);
        }

        Scene scene = new Scene(lineChart, 800, 600);
        stage.setScene(scene);
        stage.show();
    }

    public static void main(String[] args) {
        launch(args);
    }
}