关于#c++#的问题：要求编写main函数，定义两个对象T1和T2，从键盘输入对象的数值，输出两个对象之间相差的秒数

Question

定义一个时间类Time，其数据成员包括，分和秒，成员函数包括1）输入函数input，从键盘读取数据成员的数值；2）输出函数show，输出格式为例如：“25：46”3）对“-”号进行运算符重载，返回两个Time对象之间相差的秒数（返回结果为数值型）。要求编写main函数，定义两个对象T1和T2，从键盘输入对象的数值，输出两个对象之间相差的秒数

Answer 1

#include <iostream>
using namespace std;

class Time {
private:
    int minute, second;

public:
    void input() {
        cout << "Enter minutes: ";
        cin >> minute;
        cout << "Enter seconds: ";
        cin >> second;
    }

    void show() {
        cout << minute << ":" << second << endl;
    }

    int operator-(Time t) {
        int sec1 = minute * 60 + second;
        int sec2 = t.minute * 60 + t.second;
        return sec1 - sec2;
    }
};

int main() {
    Time T1, T2;

    cout << "Enter the time for T1: " << endl;
    T1.input();
    cout << "Enter the time for T2: " << endl;
    T2.input();

    cout << "T1: ";
    T1.show();
    cout << "T2: ";
    T2.show();

    int diff = T1 - T2;
    cout << "The difference between T1 and T2 is " << diff << " seconds." << endl;

    return 0;
}