dovhpmnm31216 2016-07-07 19:28
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无法在<script>标签内回显PHP变量？ [关闭]

This is my PHP code. I want error to be displayed using an alert window.

 if ($projectid=="")
  {
    $error = 'You must choose a project.
              Click &lsquo;back&rsquo; and try again.';
    include error.html.php';
    exit();
  }

This is error.html.php that is supposed to be parsed by the browser

<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="utf-8">
        <title>Script Error</title>
        <meta charset="utf-8">
        <meta http-equiv="X-UA-Compatible" content="IE=edge">
        <meta name="viewport" content="width=device-width, initial-scale=1">


    </head>

    <body>

         <script> 
             var error = <?php echo   $error ; ?>;
              window.onload = function(){ alert(error); }
         </script>
    </body>
</html>

Wahts up with the script tags ? Do they prevent PHP from running ?

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5条回答 默认 最新

  • douyu9012 2016-07-07 20:20
    关注

    The real problem is that this is what your rendered result looks like:

    var error = You must choose a project.
            Click &lsquo;back&rsquo; and try again.

    Does that looks like valid JavaScript to you? I think not.

    var error = <?=json_encode($error);?>;

    That should result in:

    var error = "You must choose a project.
                 Click &lsquo;back&rsquo; and try again.";

    Much better.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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