dqpu4988 2015-02-10 05:41
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php - 为什么foreach只运行一次?

I really was searching quite some time but I do not know what to change. My php code gets an array and I want it to insert into a mysqlDB. Problem is that it only runs the foreach loop once. Why is it not running?

public function insert_tags($projektID, $tags) {
    print_r($tags);
    foreach($tags as $tag)
        $this->db->set('name', $tag);
        $this->db->insert('tags');
        echo $tag;
        $tag_ID = $this->db->insert_id();
        echo $tag_ID;
        if ($tag_ID != 0) {
            $this->db->set('id', $projektID);
            $this->db->set('tag_ID', $tag_ID);
            $this->db->insert('hat_tags');
        }
}

It echos:

Array
(
    [0] => tag1
    [1] => tag2
)
tag2 147

No further error. Thanks for any help!

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  • dousha2020 2015-02-10 05:44
    关注

    You need to enclose them in {} brackets otherwise it will loop the first line next to it. Use the code below

    public function insert_tags($projektID, $tags) {
        print_r($tags);
        foreach($tags as $tag){
            $this->db->set('name', $tag);
            $this->db->insert('tags');
            echo $tag;
            $tag_ID = $this->db->insert_id();
            echo $tag_ID;
            if ($tag_ID != 0) {
                $this->db->set('id', $projektID);
                $this->db->set('tag_ID', $tag_ID);
                $this->db->insert('hat_tags');
            }
        }
    
    }
    

    Or you can use it with endforeach

    public function insert_tags($projektID, $tags) {
        print_r($tags);
        foreach($tags as $tag):
            $this->db->set('name', $tag);
            $this->db->insert('tags');
            echo $tag;
            $tag_ID = $this->db->insert_id();
            echo $tag_ID;
            if ($tag_ID != 0) {
                $this->db->set('id', $projektID);
                $this->db->set('tag_ID', $tag_ID);
                $this->db->insert('hat_tags');
            }
        endforeach;
    
    }
    

    Hope this helps you

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