检查单击了哪个按钮

Question

I have a PHP generated form which consists of a list of items, each with a button next to them saying "Remove This" it outputs similar to below:

Item A - [Remove This]
Item B - [Remove This]
...

I wish to be able to click Remove This and it will detect which item it is, and then remove that from the database. Here's my code so far:

selectPlaces.php

<?php
include 'data.php';

mysql_connect($host, $user, $pass) or die ("Wrong Information");

mysql_select_db($db) or die("Wrong Database");

$result = mysql_query("SELECT * FROM reseller_addresses") or die ("Broken Query");
while($row = mysql_fetch_array($result)){
    $placeName = stripslashes($row['b_name']);
    $placeCode = stripslashes($row['b_code']);
    $placeTown = stripslashes($row['b_town']);
    $outputPlaces .= "<strong>$letter:</strong> $placeName, $placeTown, $placeCode <input type=\"button\" onclick=\"removePlace()\" value=\"Remove This\" /><br />";
}

mysql_close();
?>

Coupled with my admin.php

        <div id="content" style="display:none">
        Remove a Place<br><br>
        <?php include 'selectPlaces.php'; echo $outputPlaces; ?> 
        </div>

I know I need to add some javascript to detect which button is clicked but I can't seem to get it working. I tried modifying the onclick="removePlace()" by perhaps passing a variable in the function removePlace(placeID) or something like that, but I'm new to JavaScript and I have no idea how to receive this in the removePlace function.

Answer 1

This seems easier to do without JavaScript. For each entry instead of generating just a button, generate a form that posts to a PHP script that does the deleting.

<form action="deletePlace.php?id=<?php echo $idOfThePlace?>">
<input type="submit" value="Remove This" />
</form>

$idOfThePlace would be the ID with you use to identify the data row.