a151342951 2023-05-20 23:45 采纳率: 0%
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如何用python处理txt的乱行数据

TXT文件中的串口数据出现不规则乱行

RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 
RXD: 2023/05/17: 00:57:54(774): 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00
RXD: 2023/05/17: 00:57:54(774): 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00  
RXD: 2023/05/17: 00:57:54(774): 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01 55 14 7D 01 75 01 77 01 
RXD: 2023/05/17: 00:57:54(774): 7C 01 72  01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01  
RXD: 2023/05/17: 00:57:54(774): 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 
RXD: 2023/05/17: 00:57:54(774): 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23

如何用python处理成以下文本

RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:54(464): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
RXD: 2023/05/17: 00:57:53(454): 00 00 01 55 14 7D 01 75 01 77 01 7C 01 72 01 78 00 00 00 00 00 00 00 00 00 00 0F 02 00 0A 03 03 14 55 23
  • 写回答

2条回答 默认 最新

  • threenewbee 2023-05-21 05:19
    关注

    看起来 00 00 01 是共同的前缀
    那么如果开头不是 00 00 01，就连在之前的数据后面
    遇到新的 00 00 01，再统一输出

    评论

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  • 创建了问题 5月20日