c++
void code(account* x,char a[6], char b[6])
{
int ch = 0;
char code1[6]{}, code2[6]{}, n;
cout << "密码:请输入6位数字密码:\n";
for (n = 0; n < 6;)
{
ch = _getch();//输入字符
if (ch != '\r') {
code1[n++] = ch;
printf("*");
}
}
cout << "\n确认密码:请再次输入6位数字密码:\n";
for (n = 0; n < 6;)
{
ch = _getch();//输入字符
if (ch != '\r') {
code2[n++] = ch;
printf("*");
}
else {
break;
}
}
if (strcmp(code1, code2) == 0)
{
cout << "\n确认开户\n";
x[i].code = atoi(code1);
}
else
cout << "\n两次密码不一致,未成功开户!\n";
}
`为何ATM机的密码板块 核对两次密码这里不行 一直说密码错误
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3条回答 默认 最新
qzjhjxj 2023-05-25 11:43关注这么改,供参考:
void code(account* x, char a[6], char b[6]) { int ch = 0; char code1[7]{}, code2[7]{}, n; // 修改 cout << "密码:请输入6位数字密码:\n"; for (n = 0; n < 6;) { ch = _getch();//输入字符 if (ch != '\r') { code1[n++] = ch; printf("*"); } } code1[n] = '\0'; // 修改 cout << "\n确认密码:请再次输入6位数字密码:\n"; for (n = 0; n < 6;) { ch = _getch();//输入字符 if (ch != '\r') { code2[n++] = ch; printf("*"); } else { break; } } code2[n] = '\0'; // 修改 if (strcmp(code1, code2) == 0) { cout << "\n确认开户\n"; x[i].code = atoi(code1); } else cout << "\n两次密码不一致,未成功开户!\n"; } //`为何ATM机的密码板块 核对两次密码这里不行 一直说密码错误本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报