BigDecimal 报错

Question

import java.util.*;
import java.math.*;
public class Test {
    public static void main(String[] args) {
        int cd;
        cd=0;
        try {
            BigDecimal[] a;
            a=null;
            int n,i1;
            Scanner sc=new Scanner(System.in);
            n=sc.nextInt();
            cd=1;
            a=new BigDecimal[n];
            for(i1=0; n>i1; i1++) {
                a[i1]=new BigDecimal(""+sc.nextLine());
            }
            cd=2;
            Comparator cmp = new MyComparator();
            Arrays.sort(a, cmp);
            for (BigDecimal arr : a) {
                System.out.print(arr.toString() + "\n");
            }
        } catch(Exception e) {
            System.out.println(""+e+"\n"+cd);
        }
    }
}

class MyComparator implements Comparator<BigDecimal> {
    @Override
    public int compare(BigDecimal o1, BigDecimal o2) {
        return o2.compareTo(o1);
    }
}

当我在第一行输入3时，为何会报错？

Answer 1

修改如下：

n=sc.nextInt();
sc.nextLine(); // 接收换行