PHP中的字符串数组（检查2个或更多字符串是否具有相同的开头）

Question

My question seems a little bit silly, but I don't know why I can't seem to make the code work.

I have an array of strings and want to do the following:

When I find 2, 3 or n elements starting with the same 3 letters exp 09_ I want to make it one element seperated by ***. i tried to do this

for ($j=0;$j<count($list1)-1;$j++)
    { 
        $begin= substr($list1[$j], 0, 3).'<br>';
        //echo $list1[$j].'<br>';


        if( strpos( $list1[$j], $begin ) !== false) 
        {
            $list1[$j]=$list1[$j].'***'.$list1[$j+1];
          unset($list1[$j+1]);
          $list1 = array_values($list1);
        }

        echo $list1[$j].'<br>';
    }

I have this array:

('01_order','09_customer bla bla bla ','09_customer bla1 bla1 bla1','09_customer bla2 bla2 bla2')

I want to make it look like this array

('01-order','09_customer bla bla bla * 09_customer bla1 bla1 bla1* 09_customer bla2 bla2 bla2')

Please give me some ideas

Thank you

Answer 1

Make a temporary array indexed by substrings and implode the new array's items

$res = [];

foreach($list1 as $x) { 
   $res[substr($x, 0, 3)][] = $x;
}


foreach($res as &$x) {
   $x = implode('***', (array) $x);
}

print_r($res);

demo on eval