doudian6229 2017-03-03 10:46
浏览 614
已采纳

Laravel在URL中传递参数

I have a webhook in a website, so that when a certain action is performed, one of my functions in my Laravel app is executed with the PUT method. The webhook has the following url to execute app.myapp.com/sync/documents/gt?salesID=12345.

How do I receive this parameter in Laravel?

This is my route:

Route::put('/sync/vendus/documents/gt', 'SyncController@postVendusGT');

And then in my method I have:

public function postVendusGT($request){
    dd($request->salesID);
}

But I'm getting the following error:

Missing argument 1 for App\Http\Controllers\SyncController::postVendusGT()

Am I doing this right?

  • 写回答

3条回答 默认 最新

  • doujiao3016 2017-03-03 10:49
    关注

    You need to inject the request object, this means adding the type. This tells Laravel the first parameter has to be a request object and not an url parameter.

    public function postVendusGT(Request $request) {
        dd($request->salesID);
    }
    

    More information can be found in the documentation.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?