PHP到JQuery代码转换[如果没有]

Question

How can I do it on JQuery? When I click hide, the element will be hidden, same goes for show, the element will be shown. How am I going to do it? Thanks!

<form method="POST">

<button type="submit" name="hidden" >Hide</button>
<button type="submit" name="submit" >Show</button>

</form>

<?php 

    if (isset($_POST['hidden']) == true){
        echo '*hidden*';
    } else if ($_POST['']) {
        echo 'shown';
    }

?>  

Answer 1

$(document).ready(function(){
   $(input([name='hidden']).click(function(){
      $(this).hide();
   });
    $(input([name='submit']).click(function(){
      $(input([name='hidden']).show();
   });
});