dourun2990 2016-07-11 11:42 采纳率: 100%
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如果值存在PHP,则返回数组的键

What is the fastest way to check if a variable is present in an array as its value and return the key of it?

Example:

$myArray = [ "test" => 1, "test2" = 2, "test3" = 3];

$var = [1,6,7,8,9];

What I need is if($var is in $myArray) return (in this case) "test".

Is this possible without doing two loops? Are there any functions like in_array() that returns the key of the value if found?

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  • douhui1957 2016-07-11 11:48
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    You can use array_search

    foreach($var as $value)
    {
        $key = array_search($value, $myArray);
        if($key === FALSE)
        {
            //Not Found
        }
        else
        {
            //$key contains the index you want
        }
    }
    

    Be careful, if the value is not found the function will return false but it may also return a value that can be treated the same way as false, like 0 on a zero based array so it's best to use the === operator as shown in my example above

    Check the documentation for more

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