C语言tic-tac-toe行列简化

Question

tic-tac-toe程序设计
如何对行与列进行双层循环来合并

#include<stdio.h>
int main(){
    int size = 3;
    int board[size][size];
    int i,j;
    int ret = -1;// -1表示无人赢  1表示x赢  0表示y赢
    int x,y;
    for ( i = 0; i < size; i++)
    {
        for ( j = 0; j < size; j++)
        {
            scanf("%d ",&board[i][j]); //用户输入1或O
        }
    }
    for ( i = 0; i < size && ret == -1; i++)//行
    {
        x = 0;
        y = 0;
        for ( j = 0; j < size; j++)
        {
            if (board[i][j]==1)
            {
                x += 1;
            } else 
            {
                y += 1;
            }
            
        }
    }
    for ( j = 0; j < size && ret == -1; j++)//列
    {
        x = 0;
        y = 0;
        for ( i = 0; i < size; i++)
        {
            if (board[i][j]==1)
            {
                x += 1;
            } else 
            {
                y += 1;
            }
            
        }
        if (x == size)
        {
            ret = 1;
        } else if (y == size)
        {
            ret = 0;
        }
        
    }
    for ( i = 0; i < size && ret == -1; i++)//从左至右对角线
    {
        x = 0;
        y = 0;
        for ( i = 0; i < size; i++)
        {
            if (board[i][i]==1)
            {
                x+=1;
            } else 
            {
                y+=1;
            }
             
        }
        if (x == size)
        {
            ret = 1;
        } else if (y == size)
        {
            ret = 0;
        }
    }
     for ( i = 0; i < size && ret == -1; i++)//从右至左对角线
    {
        x = 0;
        y = 0;
        for ( i = 0; i < size; i++)
        {
            if (board[i][size-i-1]==1)
            {
                x+=1;
            } else 
            {
                y+=1;
            }
             
        }
        if (x == size)
        {
            ret = 1;
        } else if (y == size)
        {
            ret = 0;
        }
        
    }
    if (ret == 1)
    {
        printf("x获胜\n");
    } 
    else if (ret == 0)
    {
        printf("y获胜\n");
    }
    else
    {
        printf("无人获胜\n");
    }
    


}

Answer 1

for ( i = 0; i < size; i++)
    {
        for ( j = 0; j < size; j++)
        {
            scanf("%d ",&board[i][j]); //用户输入1或O
        }
    }
可以写
for ( i = 0; i < size * size; i++)
{
scanf("%d",&board[i/size][i%size]);  //注意%d后面别加空格
}
别的类似