c++ 结构体与排序之奖学金

Question

c++目描述
CZ中学每学期都会给学生提供丰厚的奖学金，但是要想获得这些奖学金也不是一件容易的事情。CZ中学对学生成绩的评定一共有A、B、C共3个等级，提供的奖学金有如下几种：
A等奖学金： 总分大于等于285分，且语数英三门课的成绩均在90分以上，奖金3000元 ；
B等奖学金： 总分大于等于280分，且语数英三门课的成绩均在88分以上，奖金2000元 ；
C等奖学金： 总分大于等于275分，且语数英三门课的成绩均在85分以上，奖金1000元 ；
所有未获得奖学金的一律设置为“M”等，且奖金设为0；
在CZ中学初三（2）班共有n个学生(姓名为汉字的全拼，并且无空格)（n<10），请根据他们的成绩按照总分的高低次序，如总分相同则按照语文成绩的高低进行输出获得奖学金同学的名字、等地及金额。

输入
5
xiaoming 95 90 62
xiaoli 88 96 98
xiaozhang 86 90 89
xiaozhu 90 90 90
xiaowang 98 95 96

输出
xiaowang A 3000
xiaoli B 2000

样例
输入 复制
5
xiaoming 95 90 62
xiaoli 88 96 98
xiaozhang 86 90 89
xiaozhu 90 90 90
xiaowang 98 95 96
输出 复制
xiaowang A 3000
xiaoli B 2000

Answer 1

#include <iostream>
#include <string>
using namespace std;

struct Student {
    string name;
    int chinese;
    int math;
    int english;
    int total;
    string level;
    int scholarship;
};

void calculateScholarship(Student& student) {
    if (student.total >= 285 && student.chinese >= 90 && student.math >= 90 && student.english >= 90) {
        student.level = "A";
        student.scholarship = 3000;
    } else if (student.total >= 280 && student.chinese >= 88 && student.math >= 88 && student.english >= 88) {
        student.level = "B";
        student.scholarship = 2000;
    } else if (student.total >= 275 && student.chinese >= 85 && student.math >= 85 && student.english >= 85) {
        student.level = "C";
        student.scholarship = 1000;
    } else {
        student.level = "M";
        student.scholarship = 0;
    }
}

int main() {
    int n;
    cin >> n;
    Student students[n];
    for (int i = 0; i < n; i++) {
        cin >> students[i].name >> students[i].chinese >> students[i].math >> students[i].english;
        students[i].total = students[i].chinese + students[i].math + students[i].english;
        calculateScholarship(students[i]);
    }
    
    for (int i = 0; i < n-1; i++) {
        for (int j = 0; j < n-1-i; j++) {
            if (students[j].total < students[j+1].total) {
                swap(students[j], students[j+1]);
            } else if (students[j].total == students[j+1].total && students[j].chinese < students[j+1].chinese) {
                swap(students[j], students[j+1]);
            }
        }
    }
    
    for (int i = 0; i < n; i++) {
        if (students[i].scholarship > 0) {
            cout << students[i].name << " " << students[i].level << " " << students[i].scholarship << endl;
        }
    }
    
    return 0;
}