输出字符串的最后几个字符 - PHP / Yii

Question

How do I output just the last 3 characters of docno below? This docno outputs a really long string of numbers, and I wanted to simplify it to make it look cleaner by just showing the last 3 digits.

Yii::$app->reporter->col((isset($data[0]['docno'])? $data[0]['docno']:''),'300',null,false,'1px solid ','','L','Helvetica','11','','','').'<br />';

Thanks.

Answer 1

Use substr()

As documentation said:

If start is non-negative, the returned string will start at the start'th position in string, counting from zero. For instance, in the string 'abcdef', the character at position 0 is 'a', the character at position 2 is 'c', and so forth.

If start is negative, the returned string will start at the start'th character from the end of string.

So use negative value in second parameter

$data[0]['docno'] = substr($data[0]['docno'], -3);

Now use this in your Yii::$app->..... line