下面的C++函数:
const free_throws & clone(free_throws & ft)
{
free_throws * pt ;
*pt = ft ;
cout << "pt = " << pt << endl ;
cout << "&ft = " << &ft << endl ;
return *pt ;
}
为什么说对该函数的调用隐藏了对new的调用?
下面的C++函数:
const free_throws & clone(free_throws & ft)
{
free_throws * pt ;
*pt = ft ;
cout << "pt = " << pt << endl ;
cout << "&ft = " << &ft << endl ;
return *pt ;
}
为什么说对该函数的调用隐藏了对new的调用?