Python执行一个插入的存储过程回参获取错误

Question

执行插入存储过程运行报错，报错如下：
哪位大师解答一下啊，如何获取到select 后的 这一部分

declare @RespCode varchar(10); declare @RespMessage varchar(100); declare @OrderId varchar(20);declare @SqNo varchar(3);
 exec zsyy_LockOrder '8072','1086','0000221424','4201241972','1','2023-07-28','08：00：00','111111','PBB00000012795010','1','1','1',@RespCode output,@RespMessage output,@OrderId output,
@SqNo output;select @RespCode as RespCode, @RespMessage as RespMessage,@orderId as orderId,
@SqNo as SqNo 
No results.  Previous SQL was not a query.
Traceback (most recent call last):
  File "D:\Python\Python36\lib\site-packages\spyne\application.py", line 173, in process_request
    ctx.out_object = self.call_wrapper(ctx)
  File "D:\Python\Python36\lib\site-packages\spyne\application.py", line 242, in call_wrapper
    return ctx.descriptor.service_class.call_wrapper(ctx)
  File "D:\Python\Python36\lib\site-packages\spyne\service.py", line 194, in call_wrapper
    return ctx.function(*args)
  File "E:\python\app.py", line 552, in LockOrder
    str_xml_gxhc = insert_data(str_sql)
  File "E:\python\db_odbc.py", line 69, in insert_data
    rows = cursor.execute(str_select).fetchone()
pyodbc.ProgrammingError: No results.  Previous SQL was not a query.
192.168.000.50 - - [31/Jul/2023 09:01:52] "POST /yygh/ HTTP/1.1" 500 313

Answer 1

以下回答部分借鉴chatgpt：
根据您提供的错误信息，报错是因为前一条SQL语句不是查询语句而导致无结果返回。在执行存储过程之后，您需要使用SELECT语句来获取输出参数的值。

根据您的代码，您可以将以下部分替换到存储过程执行之后：

SELECT @RespCode as RespCode, @RespMessage as RespMessage, @orderId as orderId, @SqNo as SqNo

这样就可以通过查询语句获取到存储过程执行后的输出参数的值了。

Answer 2

谢谢.我知道后面执行可以获取.但我想一步完成.并且有问题时直接修改存储过程就行