dongpin1059 2011-08-24 15:10
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Drupal内容图像URI

I'm trying to theme a view in Drupal 7. I have the view theme set-up and it is working fine. The issue that I have is that I can't see a way to override the $content variable passed into the render() function.

Is there a pre/process hook that I should be using or should it be done in a .tpl file using the $node variable?

Currently I'm looking at the $node variable but the image attached to the content has a url of public://field/image/imagefield_JmDqqm.jpg and I've not been able to find a function (so far) that will parse that url into the correct url to view the image on the page.

Thanks for any and all help.

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  • dsfjk44656 2011-08-24 23:24
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    The file_create_url function is what you're after

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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