List<Map<String, Object>> 数组根据时间排序

Question

List<Map<String, Object>> textList = new LinkedList();
        Map<String, Object> map = new LinkedHashMap<>();
        map.put("replytime","2023-07-31 13:00:00");
        map.put("name","下午一点");
        Map<String, Object> map1 = new LinkedHashMap<>();
        map1.put("replytime","2023-07-31 14:00:00");
        map1.put("name","下午二点");
        Map<String, Object> map2 = new LinkedHashMap<>();
        map2.put("replytime","2023-07-31 15:00:00");
        map1.put("name","下午三点");
        textList.add(map);
        textList.add(map1);
        textList.add(map2);
        System.out.println("初始数组："+textList);

在不建立Bean类的情况下，根据时间字符串 对textList排序？
我要用groovy写
网上列举了用 Collections.sort(list); 但是我里面的map不是个对象，怎么处理？

Answer 1

1、新建一个list，然后把你的textList 里面所有map的replytime值存到这个list里面
2、把这个list排序
3、新建一个结果List<Map<String, Object>> resTextList,
4、遍历list，每个值比如是replytime1，在这个循环里面，遍历textList ，取每个map，判断当前map里面的replytime是否等于replytime1，等于则添加到resTextList
5、让textList =resTextList，就能排序了

        List<Map<String, Object>> textList = new LinkedList();
        Map<String, Object> map = new LinkedHashMap<>();
        map.put("replytime", "2023-07-31 14:00:00");
        map.put("name", "下午一点");
        Map<String, Object> map1 = new LinkedHashMap<>();
        map1.put("replytime", "2023-07-31 13:00:00");
        map1.put("name", "下午二点");
        Map<String, Object> map2 = new LinkedHashMap<>();
        map2.put("replytime", "2023-07-31 15:00:00");
        map1.put("name", "下午三点");
        textList.add(map);
        textList.add(map1);
        textList.add(map2);
        System.out.println("初始数组：" + textList);

        List<String> list = new LinkedList<>();
        for (Map<String, Object> stringObjectMap : textList) {
            list.add(stringObjectMap.get("replytime").toString());
        }
        System.out.println("中间数组：" + list);
        Collections.sort(list);

        List<Map<String, Object>> resTextList = new LinkedList();
        for (String s : list) {
            for (Map<String, Object> stringObjectMap : textList) {
                if (stringObjectMap.get("replytime").equals(s)) {
                    resTextList.add(stringObjectMap);
                }
            }
        }

        textList = resTextList;
        System.out.println("转换数组：" + textList);

如果有用，请给个采纳，谢谢